1×3+2×6+3×9+4×12+5×15/1×2+2×4+3×6+4×8+5×10
=1×3×(1+2²+3²+4²+5²)/[1×2×(1+2²+3²+4²+5²)]
=1×3/(1×2)
=3/2
求1×3+2×6+3×9+4×12+5×15/1×2+2×4+3×6+4×8+5×10
求1×3+2×6+3×9+4×12+5×15/1×2+2×4+3×6+4×8+5×10
数学人气:493 ℃时间:2020-03-24 14:15:00
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