The original velocity is 0,so the a=v/t=450m/s`2
Acoording to the momentum theorem:m1×v1=m2×v2
so v2=0.15×45/5.5=1.23m/s
A paintball with a mass of 0.15kg is fired from a paintball gun that has a mass of 5.5 kg.The paintball leaves the gun w
A paintball with a mass of 0.15kg is fired from a paintball gun that has a mass of 5.5 kg.The paintball leaves the gun with a velocity of 45 m/s [N] having accelerated for 0.10 s.Calculate the acceleration and the final velocity of the paintball gun.
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