已知2的96次方减一可以被在60-70之间的两个数整除,则这两个数是多少

2^96-1=(2^48+1)(2^48-1)=(2^48+1)(2^24+1)(2^24-1)=(2^48+1)(2^24+1)(2^12+1)(2^12-1)=(2^48+1)(2^24+1)(2^12+1)(2^6+1)(2^6-1)(2^6+1)就是64+1=65(2^6-1)就是64-1=63