(x-2)^2-(x-1)^2+1
=x^2-4x+4-x^2+2x-1+1
=-2x+2
=-2(x-2)
所以:
(x-2)分之[(x-2)^2-(x-1)^2+1]=-2
已知x2-5x-2009=0,求代数式(x-2)分之[(x-2)^2-(x-1)^2+1]
已知x2-5x-2009=0,求代数式(x-2)分之[(x-2)^2-(x-1)^2+1]
数学人气:870 ℃时间:2020-01-30 07:32:29
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