y+z=may+mbz
z+x=maz+mby
x+y=max+mbz
相加
2(x+y+z)=my(a+b)+mz(a+b)+mx(a+b)=m(a+b)(x+y+z)
应该还有x+y+z不等于0
所以m=2/(a+b)
已知y+z/ay+bz=z+x/az+bx=x+y/ax+by=m,求证：m=2/a+b
已知y+z/ay+bz=z+x/az+bx=x+y/ax+by=m,求证：m=2/a+b
数学人气：906 ℃时间：2019-11-16 06:47:15
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