令y=loga(x+√(x^-1)
则a^y=x+√(x^-1)
x√(x)=1÷(a^y-1)
x^3=(a^y-1)^(-2)
x=(a^y-1)^(-2/3)
故f^(-1)(x)=(a^x-1)^(-2/3)
当0
设a>0,a≠1,f(x)=loga(x+√(x^-1) (x≥1),求f(x)的反函数
设a>0,a≠1,f(x)=loga(x+√(x^-1) (x≥1),求f(x)的反函数
并求出定义域
并求出定义域
数学人气:440 ℃时间:2019-09-26 00:07:38
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