利用因式分解,说明3的24次方减1可被8整除

x^24-1=(x^(12))^2-1=(x^12+1)(x^12-1)=(x^12+1)((x^6)^2-1)=(x^12+1)(x^6+1)(x^6-1)=(x^12+1)(x^6+1)((x^3)^2-1)=(x^12+1)(x^6+1)(x^3+1)(x^3-1)当x=3则:x^12+1,x^6+1,x^3+1都是偶数所以:3的24次方减1可被:2*2*2=8...