1.（sin^4x-sin^2x）/secx
=sin^2x(sin^2x-1)cosx
=-sin^2xcos^2xcosx
=-sin^2xcos^3x
2.sin^4x-cos^4x
=(sin^2x+cos^2x)(sin^2x-cos^2x)
=sin^2x-cos^2x
化简【完整步骤!】
化简【完整步骤!】
1.（sin^4x-sin^2x）/secx
2.sin^4x-cos^4x
【这道题的正确答案是sin^2x-cos^2x】
1.（sin^4x-sin^2x）/secx
2.sin^4x-cos^4x
【这道题的正确答案是sin^2x-cos^2x】
数学人气：718 ℃时间：2020-03-26 20:55:52
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