以知A(m,1+m,2+m),B(1-m,3-2m,3m)是空间两个动点,求|AB|（AB上面有"→")的最小值

p(AB)=P(AUB上面横杠)
=> P(AB) = 1-P(AUB)
=> P(AB) = 1-[P(A)+P(B)-P(AB)]
=> 0 = 1-P(A)-P(B)
=> P(B) = 1-P(A)
=> P(B) = 1-p这是关于向量的问题！