求积分 ∫1到8 [(x^1/3+1)(2-x^2/3)]/x^1/3 dx

=∫[x^(1/3)-x+2-x^(2/3)]/x^(1/3)]dx
=∫[1-x^(2/3)+2x^(-1/3)-x^(1/3)]]dx
幂函数积分
=x-x^(5/3)/(5/3)+2x^(2/3)/(2/3)-x^(4/3)/(4/3)(1,8)
代入算一下吧是g(8)-g(1） 就可以了吗 ？谢谢~对，算起来挺麻烦，囧