f(x)=√3sinωx+cosωx
=2(sinωx*√3/2+cosωx*1/2)
=2(sinωx*cosπ/6+cosωx*sinπ/6)
=2sin(ωx+π/6)
函数f(x)=根号3sinωx+cosωx(ω>0)怎样变为f(x)=2sin(ωx+π/6)
函数f(x)=根号3sinωx+cosωx(ω>0)怎样变为f(x)=2sin(ωx+π/6)
数学人气:183 ℃时间:2019-10-10 06:51:29
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