∴ab-2=0,b+1=0,
解得:a=-2,b=-1;
(2)当a=-2,b=-1时,b2011−(
a |
2 |
−2 |
2 |
=-1-(-1)
=0.
(3)当a=-2,b=-1时,
1 |
ab |
1 |
(a−1)(b−1) |
1 |
(a−2)(b−2) |
1 |
(a−2012)(b−2012) |
=
1 |
(−2)×(−1) |
1 |
(−3)×(−2) |
1 |
(−4)×(−3) |
1 |
(−2014)×(−2013) |
=1-
1 |
2 |
1 |
2 |
1 |
3 |
1 |
3 |
1 |
4 |
1 |
2013 |
1 |
2014 |
=1-
1 |
2014 |
=
2013 |
2014 |