连接AC,AD
因为AB=AE,BC=ED,∠B=∠E
所以⊿ABC≌⊿AED
所以 AC=AD
又因为AF垂直CD于F,
所以 CF=DF(等腰三角形的高与中线重合)
AB=AE,BC=ED,∠B=∠E,AF垂直CD于F,求证:CF=DF
AB=AE,BC=ED,∠B=∠E,AF垂直CD于F,求证:CF=DF
该图形是个5边形,AF平分角BAE、
该图形是个5边形,AF平分角BAE、
其他人气:419 ℃时间:2019-10-31 01:14:28
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