帮忙求一下不定积分（2的x次方+1/3的x次方+e的x次方/5）dx急!

∫[2^x+(1/3)^x+e^x/5]dx=∫2^xdx+∫(1/3)^xdx+∫e^x/5dx=(1/ln2)*∫2^xln2dx+1/ln(1/3)*∫(1/3)^xln(1/3)dx+∫e^x/5dx=2^x/ln2+(1/3)^x/ln(1/3)+e^x/5+C=2^x/ln2-(1/3)^x/ln3+e^x/5+C