解方程组√2x-y=√2,x²-y²/4=1

你好,√2x-y=√2,√2x-y-√2=0√2(x-1)=y带入x²-y²/4=1,得4x²-（√2(x-1)）²=4即4x²-2x²+4x-2-4=0x²+2x-3=0（x-1)(x+3)=0,得出x1=1,x2=-3y1=0,y2=-4√2方程组的有x1y1,x1y2,x2y1...