2^32-1
=(2^16-1)(2^16+1)
=(2^8-1)(2^8+1)(2^16+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1) 2^4=16
=15*17*(2^8+1)(2^16+1)
2^32-1能被10于20之间的两个整数整除,这两个整数,为15和17说明理由?2^32-1=15*17*(2^8+1)(2^16+1)右边有因数15,17所以 这两个整数,为15和17
2^32-1能被10于20之间的两个整数整除,找出这两个整数,并说明理由
2^32-1能被10于20之间的两个整数整除,找出这两个整数,并说明理由
数学人气:564 ℃时间:2020-01-24 10:12:11
优质解答
我来回答
类似推荐
猜你喜欢
- 15:7=(360-x):x如何计算
- 2判断题.对的打,错的打.
- 3要亨利福特的英文简介?急用!
- 4—when you leave the office,make sure the door ---- _ok,I will A,was locked B will be locked
- 5甲乙两数的比是3:5,乙数比甲数多12,甲数是_,乙数是_.
- 6I want to keep a cat,but my parents don't want to buy____for me.
- 7如何用一次函数图象二元一次方程组近似解?
- 8Who do you sometimes wait at the school gate?(改错)
- 9不等式性质:a1约等于根号2,令a2= 1 + (1/(1+a1)).(1)证明……
- 10Last year,there 15 students in our team.This year,there are 20 students in our team.(变同义句)