化简:根号(1-sinx)+根号(1+sinx),x属于(0,π)

x属于(0,π) ,则x/2属于(0,π/2),则sin(x/2)＞0,cos(x/2)＞0根号(1-sinx)+根号(1+sinx),=根号[sin²(x/2)+cos²(x/2)-2sin(x/2)cos(x/2)]+根号[sin²(x/2)+cos²(x/2)+2sin(x/2)cos(x/2)]=根号[sin(...