A={x|x²-3x+4=0}=Φ
B={x|(x+1)(x+4)(x-1)=0}={-4,-1,1}
∴P有以下7种可能:
P={-4},P={-1},P={1}
P={-4,-1},P={-4,1},P={-1,1}
P={-4,-1,1}
集合A={x²-3x+4=0,x∈R},B={x|(x+1)(x²+3x-4)=0,x∈R},又A真子集P子集B,求满足条件
集合A={x²-3x+4=0,x∈R},B={x|(x+1)(x²+3x-4)=0,x∈R},又A真子集P子集B,求满足条件
数学人气:592 ℃时间:2020-04-09 02:01:14
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