若a与2b互为倒数,-c与d互为相反数,|x|=3,则2ab-2c+ x/3 +2d的值为多少? x/3指三分之x

若a与2b互为倒数,2ab=1
因为-c与d互为相反数,所以-c+d=0,所以c=d
因为,|x|=3,所以x=3或-3
2ab-2c+ x/3 +2d=1-2d+3/3+2d=2
或2ab-2c+ x/3 +2d=1-2d-3/3+2d=0