急!y＝1/(x＋√(1＋x∧2))求导,结果.
急!y＝1/(x＋√(1＋x∧2))求导,结果.
数学人气：442 ℃时间：2019-09-10 09:07:58
优质解答
y=1/[x+√(1+x^2)]那么y'= -1/[x+√(1+x^2)]^2 * [x+√(1+x^2)]'而[x+√(1+x^2)]'= 1 +x/√(1+x^2)=[x+√(1+x^2)] / √(1+x^2)所以y'= -1/[x+√(1+x^2)]^2 * [x+√(1+x^2)]'= -1/[x+√(1+x^2)]^2 *[x+√(1+x^2)] / ...
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