[(b-3a)的2次方]的n+1次方乘于【（3a-b）的2n+1次方】的3次方 （n为正整数） 要求计算

[(b-3a)²]^(n+1)×【（3a-b)^(2n+1)】³
=[(3a-b)²]^(n+1)×【（3a-b)^(2n+1)】³
=(3a-b)^(2n+2)×(3a-b)^(6n+3)
=(3a-b)^[(2n+2)+(6n+3)]
=(3a-b)^(8n+5)