已知函数fx=2sin(2x+π/3)+2 求

1、最小正周期T=2π/2=π;最大值=2×1+2=4；2、单调递增式时-π/2+2kπ≤2x+π/3≤π/2+2kπ(k∈Z)-5π/6+2kπ≤2x≤π/6+2kπ(k∈Z)-5π/12+kπ≤x≤π/12+kπ(k∈Z)∴单调递增区间为[-5π/12+kπ,π/12+kπ](k∈Z)...