22应该是32
2*(3+1)*(3^2+1)*(3^4+1)*……*(3^32+1)+1
=(3-1)*(3+1)*(3^2+1)*(3^4+1)*……*(3^32+1)+1
=(3^2-1)*(3^2+1)*(3^4+1)*……*(3^32+1)+1
=(3^4-1)*(3^4+1)*……*(3^32+1)+1
反复用平方差
=3^64-1+1
=3^64
2*(3+1)*(3^2+1)*(3^4+1)*……*(3^22+1)+1怎么算
2*(3+1)*(3^2+1)*(3^4+1)*……*(3^22+1)+1怎么算
数学人气:199 ℃时间:2020-01-28 05:24:08
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