甲乙两个篮球员,投篮命中0.7和0.6,每人投篮3次,求两人进球相等的概率

用X表示进球数,P表示概率
X甲=X乙=0,P=0.3*0.3*0.3*0.4*0.4*0.4=0.001728
X甲=X乙=1,P=C（3,1）*0.7*0.3*0.3*C（3,1）*0.6*0.4*0.4=0.054432
X甲=X乙=2,P=C（3,2）*0.7*0.7*0.3*C（3,2）*0.6*0.6*0.4=0.190512
X甲=X乙=3,P=0.7*0.7*0.7*0.6*0.6*0.6=0.074088
P（X甲=X乙）=0.001728+0.054432+0.190512+0.074088=0.32076
两人进球相等的概率是0.32076!