tan30°+sin60°-tan45°+cos0°＝?

因为tan30°=√3/3,sin60°=√3/2,tan45°=1,cos0°=1
所以
tan30°+sin60°-tan45°+cos0°
=√3/3+√3/2-1+1
=2√3/6+3√3/6
=(2√3+3√3)/6
=5√3/6谢谢再来一道吧呵呵sin30°－tan45°－cos45°－sin²60°＋4分之3tan²30°你好因为sin30°=1/2, tan45°=1,cos45°=√2/2, sin60°=√3/2, tan30°=√3/3所以sin30°-tan45°-cos45°-sin²60°+3tan²30°/4=1/2-1-√2/2-(√3/2)²+3×(√3/3)²/4=1/2-1-√2/2-3/4+1/4=-1-√2/2=(-2-√2)/2