已知：a+b=根号2010+根号2009的正平方根,a-b=根号2010-根号2009的正平方根,求（a乘b）平方的值.

a+b = √{√2010+√2009}
a-b = √{√2010-√2009}
ab = 1/4{(a+b)²-(a-b)²} = 1/4{(√2010+√2009)-(√2010-√2009)} = 1/4×2√2009 = 1/2×√2009
(ab)² = {1/2×√2009}² = 2009/4