原不等式化为
5x^2 - 10x + 3 >= 3x^2 - 7x+ 2
移项得
2x^2 - 3x + 1 >= 0
即
(2x - 1)(x - 1) >= 0
解得
x >=1 或者x =1或x
解不等式:(5x^2-10x+3)/(3x^2-7x+2)>=1
解不等式:(5x^2-10x+3)/(3x^2-7x+2)>=1
数学人气:400 ℃时间:2020-01-26 03:07:40
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