求因式分解(X^4-4X^2+1)(X^4+3X^2+1)+10X^4

原式=[(x^4+1)-4x²][(x^4+1)+3x²]+10x^4
=(x^4+1)²-x²(x^4+1)-12x^4+10x^4
=(x^4+1)²-x²(x^4+1)-2x^4
=(x^4+1-2x²)(x^4+1+x²)
=(x²-1)²[(x^4+2x²+1)-x²]
=(x+1)²(x-1)²[(x²+1)²-x²]
=(x+1)²(x-1)²(x²+x+1)(x²-x+1)