lim |
n→∞ |
1 |
1•4 |
1 |
4•7 |
1 |
7•10 |
1 |
(3n−2)(3n+1) |
=
lim |
n→∞ |
1 |
3 |
1 |
4 |
1 |
4 |
1 |
7 |
1 |
3n−2 |
1 |
3n+1 |
=
lim |
n→∞ |
1 |
3 |
1 |
3n+1 |
=
lim |
n→∞ |
1 |
3 |
3n |
3n+1 |
1 |
3 |
故答案为
1 |
3 |
lim |
n→∞ |
1 |
1•4 |
1 |
4•7 |
1 |
7•10 |
1 |
(3n−2)(3n+1) |
lim |
n→∞ |
1 |
1•4 |
1 |
4•7 |
1 |
7•10 |
1 |
(3n−2)(3n+1) |
lim |
n→∞ |
1 |
3 |
1 |
4 |
1 |
4 |
1 |
7 |
1 |
3n−2 |
1 |
3n+1 |
lim |
n→∞ |
1 |
3 |
1 |
3n+1 |
lim |
n→∞ |
1 |
3 |
3n |
3n+1 |
1 |
3 |
1 |
3 |