lim[1+3+5+…+(2n-1)/[n(2n-1)]等于多少?
lim[1+3+5+…+(2n-1)/[n(2n-1)]等于多少?
数学人气：659 ℃时间：2020-05-24 08:14:04
优质解答
1+3+5+…+(2n-1) = n(2n-1+1)/2 = n^2[1+3+5+…+(2n-1)/[n(2n-1)] = (n^2)/[n(2n-1)] = n/(2n-1) = 1/(2 - 1/n)lim[1+3+5+…+(2n-1)/[n(2n-1)] = lim[1/(2 - 1/n)] = 1/2
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