将分式10X^2+30X+20/X^3+2X^2－X－2 约分,再将使分试值为正整数时,求整数X的值?
将分式10X^2+30X+20/X^3+2X^2－X－2 约分,再将使分试值为正整数时,求整数X的值?
数学人气：431 ℃时间：2020-03-14 13:52:08
优质解答
(10X^2+30X+20)/(X^3+2X^2－X－2) =10(X+2)(X+1)/[X^2*(X+2)-(X+2)] =10(X+2)(X+1)/[(X-1)(X+1)(X+2)] =10/(X-1) 若分数值为正整数值,则X=2或X=3或X=6或X=11
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