解不等式:A={x| x^2-2x-3>0}={x| x3};B={x |x^2 + 2x + 3 >0}=R(因为x^2+2x+3>0对x属于R恒成立).A∩B=(负无穷,-1)并(3,正无穷);
A∪B=R;
A∩CuB=空集
已知全集U=R,集合A={x| x^2-2x-3>0},B={x |x^2 + 2x + 3 >0},求A∩B,A∪B,A∩CuB
已知全集U=R,集合A={x| x^2-2x-3>0},B={x |x^2 + 2x + 3 >0},求A∩B,A∪B,A∩CuB
请各位老师指教下,
请各位老师指教下,
数学人气:438 ℃时间:2020-01-24 13:07:18
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