当x=3时,求X的平方-X-2分之3x+2+（1-X+1分之1）除以（1+X-1分之1）的值

(3x+2)/(x²-x-2)+[1-1/(x+1)]÷[1+1/(x-1)]=(3x+2)/(x-2)(x+1)+[(x+1-1)/(x+1)]÷[(x-1+1)/(x-1)]=(3x+2)/(x-2)(x+1)+x/(x+1)*(x-1)/x=(3x+2)/(x-2)(x+1)+(x-1)/(x+1)=[3x+2+(x-1)(x-2)]/(x-2)(x+1)=(x²+4...