-1≤(2m-1)/(3m+2)≤1
不等式同乘以(3m+2)²得-(3m+2)²≤(2m-1)(3m+2)≤(3m+2)²,因为(3m+2)²是正的,不变号.
可拆成两个不等式来解,
15m²+13m+2≥0,分解因式得(3m+2)(5m+1)≥0,所以m≥-1/5或m≤-2/3.
3m²+11m+6≥0,分解因式得(3m+2)(m+3)≥0,所以m≤-3或m≥-2/3.
然后你画个数轴,综上有m≤-3或m≥-1/5.
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