解方程.（5x/x²+x-6）+（2x-5/x²-x-12）=7x-10/x²-6x+8

5x/(x²+x-6)+(2x-5)/(x²-x-12)=(7x-10)/(x²-6x+8)5x/[(x+3)(x-2)]+(2x-5)/[(x-4)(x+3)]=(7x-10)/[(x-2)(x-4)]通分化简,得5x(x-4)+(2x-5)(x-2)=(7x-10)(x+3)整理,得40x=40x=1代回原方程检验,分母有意...