求解微分方程y'*cos(y)=x+1-sin(y)

y ' * cos(y) = x + 1 - sin(y) => y ' * cos(y) - 1 = x - sin(y) =>(sin(y) - x) ' = x - sin(y) => 换元 sin(y) - x = tt ' = dt / dx = -t =>1/t dt = -1 dx 两边积分 => ln t = -x + C1 => t = C * e^(-x).即 s...