1.806*10^23÷(6.02*10^23每mol)
=0.3mol
由于1mol锌反应能转移2mol电子,转移0.3mol需要锌0.15mol.
故反应的锌为0.15mol.
理解请及时采纳!祝你进步!
用Zn和硫酸制取H2,若失去1.806*10^23电子,则反映Zn( )mol
用Zn和硫酸制取H2,若失去1.806*10^23电子,则反映Zn( )mol
化学人气:662 ℃时间:2020-02-05 07:02:20
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