∫x^6/(1-x^4)dx不定积分

∫x^6/(1-x^4)dx=∫[x^2-x^2(1-x^4)]/(1-x^4)dx=∫[-x^2+x^2/(1-x^4)] dx=-1/3*x^3+∫x^2/(1-x^4)dx=-1/3*x^3-1/2*∫[1/(1-x^2)-1/(1+x^2)]dx=-1/3*x^3-1/2*[∫1/(1-x^2)dx-∫1/(1+x^2)dx]=-1/3*x^3-1/2*{1/2*∫[1/(...