设B点坐标为(xb,xb^2+3),P为(x0,y0)
则
2x0=xb+6
2y0=xb^2+3
由得xb=2x0-6,代入得
2y0=39-24 x0+4x0^2
化简得y0=2x0^2-12x0+39/2
所以P的轨迹方程为y=2x^2-12x+39/2
已知,线段AB,A(6,0),B点在曲线c y=x^2+3上移动,求AB中点P的轨迹方程
已知,线段AB,A(6,0),B点在曲线c y=x^2+3上移动,求AB中点P的轨迹方程
数学人气：169 ℃时间：2020-01-27 12:10:02
优质解答
我来回答
类似推荐
猜你喜欢
- 1He works from dawn to dusk to keep the wolf from the door.
- 2lc并联谐振电路中谐振频率确定,LC的乘积就确定了,那是否L值可以取的很大C值取的很小呢
- 31.when I grow up,I want to go a ___ to learn about different countries.2.the bridge ___(连接) the
- 4they arrived at last 用英文解释
- 5两个数相除得4.6,如果被除数不变,除数缩小10倍,商是?
- 6-I like bands that______really cool clithes.-That's not relly impoant___me.
- 7英语单词的反义词~
- 8四年级上册数学笔算题75道
- 9英语几个用词的区分
- 10can you give me a cup of tea?改为同义句.can you _____ _____ _____ _____ _____ _____ _____