∵b=[根号下{(a的2次方)-4}+根号下{4- (a的二次方)}除以(a+2)]+7,
∴a²-4≥0 4-a²≥0 a+2≠0
故a²-4=0
a=2
∴b=[根号下{(a的2次方)-4}+根号下{4- (a的二次方)}除以(a+2)]+7
b=[0+0/(0±2)]+7
b=7
∴a+b的平方根=±√7
若a,b为实数,且b=[根号下{(a的2次方)-4}+根号下{4- (a的二次方)}除以(a+2)]+7,求a+b的平方根
若a,b为实数,且b=[根号下{(a的2次方)-4}+根号下{4- (a的二次方)}除以(a+2)]+7,求a+b的平方根
{}为中括号,()为小括号,[为大括号]
{}为中括号,()为小括号,[为大括号]
数学人气:608 ℃时间:2019-10-29 19:15:11
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