{an}等比数列,且an>0,a1*a100=100 则 lga1+lga2+...+lga100=
{an}等比数列,且an>0,a1*a100=100 则 lga1+lga2+...+lga100=
数学人气:617 ℃时间:2020-04-06 17:54:43
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lga1+lga2+...+lga100=lga1*a2*.*a99*a100由{an}等比数列,得a1*a100=a2*a99=a3*a98=.=a50*a51=100而a1*a2*.*a99*a100=a1*a100*a2*a99*a3*a98*.*a50*a51=100^(100/2)=100^50=10^100从而 lga1+lga2+...+lga100=lga1*a...
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