a1+a8=a4+a5=387
a4*a5=1152
a4=3 a5=384或a4=384 a5=3
所以an=3（128）^(n-4)或384(128）^(4-n)
数列an为等比数列,若a1+a8=387,a4*a5=1152,则此数列的通项an为
数列an为等比数列,若a1+a8=387,a4*a5=1152,则此数列的通项an为
数学人气：189 ℃时间：2020-04-16 02:09:46
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