原式=(x²+3x+9)/(x-3)(x²+3x+9)-6x/x(x-3)(x+3)-(x-1)/2(x+3)
=1/(x-3)-6/(x-3)(x+3)-(x-1)/2(x+3)
=(2x+6-12-x²+4x-3)/2(x+3)(x-3)
=-(x²-6x+9)/2(x+3)(x-3)
=-(x-3)²/2(x+3)(x-3)
=(3-x)/(2x+6)
(x2+3x+9)/(x2-27)+(6x)/(9x-x2)-(x-1)/(6+2x)
(x2+3x+9)/(x2-27)+(6x)/(9x-x2)-(x-1)/(6+2x)
详细解题过程,谢谢!
x后面的2是指平方。请高手帮忙解一下,感激不尽!!!
不是解方程,是化简!!!
详细解题过程,谢谢!
x后面的2是指平方。请高手帮忙解一下,感激不尽!!!
不是解方程,是化简!!!
数学人气:348 ℃时间:2020-01-28 00:21:00
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