一道分式数学题,
一道分式数学题,
1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)+.+1/(a+2004))(a+2005)=?
1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)+.+1/(a+2004))(a+2005)=?
数学人气：941 ℃时间：2020-04-07 20:33:15
优质解答
∵1/a(a+1)=1/a -1/(a+1)1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)+.+1/(a+2004))(a+2005)∴原式=1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)+.+1/(a+2004))(a+2005)=1/a-1/(a+1)+1/(a+1)-1/(a+2)+..-1/(a+2004)+1/(a+2004)-1/(a...
我来回答
类似推荐