1除以x-1 - （除以x-2）等于1除以x-3-（1除以x-4）

1/(x-1)+1/(x-4)-[1/(x-2)+1/(x-3)]=0通分(2x-5)/(x²-5x+4)-(2x-5)/(x²-5x+6)=0(2x-5)[1/(x²-5x+4)-1/(x²-5x+6)]=0x²-5x+4≠x²-5x+6所以1/(x²-5x+4)-1/(x²-5x+6)≠0所以2x-...