∵a2-2a+1=0,
∴a2-2a=-1
2a2-4a+5=2(a2-2a)+5
=2×(-1)+5=3.
若实数a满足a2-2a+1=0,则2a2-4a+5=_.
若实数a满足a2-2a+1=0,则2a2-4a+5=______.
数学人气:856 ℃时间:2020-02-05 07:27:38
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