分析:把()3x+2y)看成是一个整体,再用"十"字相乘法,
(3x+2y-3)(3x+2y+7)-11
=(3x+2y)²+4(3x+2y)-21-11
=(3x+2y)²+4(3x+2y)-32
=[(3x+2y)+8][(3x+2y)-4]
=(3x+2y+8)(3x+2y-4)
因式分解：(3x+2y-3)(3x+2y+7)-11
因式分解：(3x+2y-3)(3x+2y+7)-11
数学人气：385 ℃时间：2020-03-25 08:14:08
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