原式=x(x+4)/(x-2)(x+4)-(x+2)/(x+2)(x-2)
=x/(x-2)-1/(x-2)
=(x-1)/(x-2)计算a+b分之b²-【b】采纳我,重新问
计算:【x-2】【x+4】分之x²+4x-x²-4分之x+2=
计算:【x-2】【x+4】分之x²+4x-x²-4分之x+2=
数学人气:194 ℃时间:2020-03-27 03:38:20
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