∵y=x^(sinx)
∴lny=sinx*lnx
两边求导：y'/y=cosx*lnx+(sinx)/x
∴y'=y[cosx*lnx+(sinx)/x]=x^(sinx)[cosx*lnx+(sinx)/x]
∴导数为：x^(sinx)[cosx*lnx+(sinx)/x]
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