(a-2b)(2a+b)
=2a^2-3ab-2b^2
=8-18cosx-18
=-10-18cosx=-1
所以cosx=-1/2
x=120度
已知向量a,b满足|a|=2,|b|=3,且(a-2b)(2a+b)=-1,则a与b的夹角为?
已知向量a,b满足|a|=2,|b|=3,且(a-2b)(2a+b)=-1,则a与b的夹角为?
数学人气：831 ℃时间：2019-11-04 02:28:13
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